13044000127 has 2 divisors, whose sum is σ = 13044000128. Its totient is φ = 13044000126.

The previous prime is 13044000037. The next prime is 13044000131. The reversal of 13044000127 is 72100044031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13044000127 is a prime.

It is a super-2 number, since 2×13044000127² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044000098 and 13044000107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044000527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522000063 + 6522000064.

It is an arithmetic number, because the mean of its divisors is an integer number (6522000064).

Almost surely, 2^13044000127 is an apocalyptic number.

13044000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044000127 is an equidigital number, since it uses as much as digits as its factorization.

13044000127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 22.

Adding to 13044000127 its reverse (72100044031), we get a palindrome (85144044158).

The spelling of 13044000127 in words is "thirteen billion, forty-four million, one hundred twenty-seven", and thus it is an aban number.