13044000443119 has 4 divisors (see below), whose sum is σ = 13044007932640. Its totient is φ = 13043992953600.

The previous prime is 13044000443099. The next prime is 13044000443161. The reversal of 13044000443119 is 91134400044031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13044000443119 - 2³⁹ = 12494244629231 is a prime.

It is a super-3 number, since 3×13044000443119³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044000446119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388042 + ... + 5122360.

It is an arithmetic number, because the mean of its divisors is an integer number (3261001983160).

Almost surely, 2^{13044000443119} is an apocalyptic number.

13044000443119 is a deficient number, since it is larger than the sum of its proper divisors (7489521).

13044000443119 is an equidigital number, since it uses as much as digits as its factorization.

13044000443119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7489520.

The product of its (nonzero) digits is 20736, while the sum is 34.

The spelling of 13044000443119 in words is "thirteen trillion, forty-four billion, four hundred forty-three thousand, one hundred nineteen".