Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100101001001001110100011 |
3 | 122002211221110201020101102212 |
4 | 131222021232211021032203 |
5 | 114044112121033313103 |
6 | 1141231151514232335 |
7 | 36321660045115154 |
oct | 3552115645111643 |
9 | 562757421211385 |
10 | 130440012010403 |
11 | 38620331241217 |
12 | 127681941256ab |
13 | 57a25955bc714 |
14 | 242d48a37792b |
15 | 101309da4c7d8 |
hex | 76a26e9493a3 |
130440012010403 has 2 divisors, whose sum is σ = 130440012010404. Its totient is φ = 130440012010402.
The previous prime is 130440012010397. The next prime is 130440012010447. The reversal of 130440012010403 is 304010210044031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130440012010403 - 216 = 130440011944867 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (130440012010103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006005201 + 65220006005202.
It is an arithmetic number, because the mean of its divisors is an integer number (65220006005202).
Almost surely, 2130440012010403 is an apocalyptic number.
130440012010403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440012010403 is an equidigital number, since it uses as much as digits as its factorization.
130440012010403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 130440012010403 its reverse (304010210044031), we get a palindrome (434450222054434).
The spelling of 130440012010403 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, ten thousand, four hundred three".
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