Base | Representation |
---|---|
bin | 1011110111010000101100… |
… | …0011101101110011110101 |
3 | 1201011222211212112011020022 |
4 | 2331310023003231303311 |
5 | 3202203103301421042 |
6 | 43424155331014525 |
7 | 2514253336551365 |
oct | 275641303556365 |
9 | 51158755464208 |
10 | 13044001201397 |
11 | 4179a25692651 |
12 | 156802173a445 |
13 | 73807599016a |
14 | 331493b7a9a5 |
15 | 17948757ecd2 |
hex | bdd0b0edcf5 |
13044001201397 has 2 divisors, whose sum is σ = 13044001201398. Its totient is φ = 13044001201396.
The previous prime is 13044001201351. The next prime is 13044001201421. The reversal of 13044001201397 is 79310210044031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10255071141316 + 2788930060081 = 3202354^2 + 1670009^2 .
It is a cyclic number.
It is not a de Polignac number, because 13044001201397 - 214 = 13044001185013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13044001201597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522000600698 + 6522000600699.
It is an arithmetic number, because the mean of its divisors is an integer number (6522000600699).
Almost surely, 213044001201397 is an apocalyptic number.
It is an amenable number.
13044001201397 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044001201397 is an equidigital number, since it uses as much as digits as its factorization.
13044001201397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 13044001201397 in words is "thirteen trillion, forty-four billion, one million, two hundred one thousand, three hundred ninety-seven".
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