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13044001233073 is a prime number
BaseRepresentation
bin1011110111010000101100…
…0011110101100010110001
31201011222211212120202200111
42331310023003311202301
53202203103303424243
643424155331421321
72514253340042626
oct275641303654261
951158755522614
1013044001233073
114179a25704428
121568021754841
137380759a16c5
14331493b8834d
1517948758939d
hexbdd0b0f58b1

13044001233073 has 2 divisors, whose sum is σ = 13044001233074. Its totient is φ = 13044001233072.

The previous prime is 13044001233019. The next prime is 13044001233083. The reversal of 13044001233073 is 37033210044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11472771573904 + 1571229659169 = 3387148^2 + 1253487^2 .

It is an emirp because it is prime and its reverse (37033210044031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13044001233073 is a prime.

It is not a weakly prime, because it can be changed into another prime (13044001233083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522000616536 + 6522000616537.

It is an arithmetic number, because the mean of its divisors is an integer number (6522000616537).

Almost surely, 213044001233073 is an apocalyptic number.

It is an amenable number.

13044001233073 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044001233073 is an equidigital number, since it uses as much as digits as its factorization.

13044001233073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 31.

The spelling of 13044001233073 in words is "thirteen trillion, forty-four billion, one million, two hundred thirty-three thousand, seventy-three".