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13044012024013 = 16078116995659
BaseRepresentation
bin1011110111010000101110…
…1101000000000011001101
31201011222212121220000001221
42331310023231000003031
53202203114034232023
643424200355003341
72514253530545245
oct275641355000315
951158777800057
1013044012024013
114179a30804863
121568025299551
13738077cac289
14331495396b25
151794884bb85d
hexbdd0bb400cd

13044012024013 has 4 divisors (see below), whose sum is σ = 13052129021280. Its totient is φ = 13035895026748.

The previous prime is 13044012023969. The next prime is 13044012024019. The reversal of 13044012024013 is 31042021044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044012024013 - 221 = 13044009926861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044012024019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4058496223 + ... + 4058499436.

It is an arithmetic number, because the mean of its divisors is an integer number (3263032255320).

Almost surely, 213044012024013 is an apocalyptic number.

It is an amenable number.

13044012024013 is a deficient number, since it is larger than the sum of its proper divisors (8116997267).

13044012024013 is an equidigital number, since it uses as much as digits as its factorization.

13044012024013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8116997266.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044012024013 its reverse (31042021044031), we get a palindrome (44086033068044).

The spelling of 13044012024013 in words is "thirteen trillion, forty-four billion, twelve million, twenty-four thousand, thirteen".

Divisors: 1 1607 8116995659 13044012024013