1304401210403 has 4 divisors (see below), whose sum is σ = 1304416967568. Its totient is φ = 1304385453240.

The previous prime is 1304401210313. The next prime is 1304401210459. The reversal of 1304401210403 is 3040121044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304401210403 - 2¹⁸ = 1304400948259 is a prime.

It is a super-2 number, since 2×1304401210403² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304401216403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7753751 + ... + 7920192.

It is an arithmetic number, because the mean of its divisors is an integer number (326104241892).

Almost surely, 2^{1304401210403} is an apocalyptic number.

1304401210403 is a deficient number, since it is larger than the sum of its proper divisors (15757165).

1304401210403 is an equidigital number, since it uses as much as digits as its factorization.

1304401210403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15757164.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1304401210403 its reverse (3040121044031), we get a palindrome (4344522254434).

The spelling of 1304401210403 in words is "one trillion, three hundred four billion, four hundred one million, two hundred ten thousand, four hundred three".