13044014110121 has 4 divisors (see below), whose sum is σ = 13238700887952. Its totient is φ = 12849327332292.

The previous prime is 13044014110117. The next prime is 13044014110129. The reversal of 13044014110121 is 12101141044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044014110121 - 2² = 13044014110117 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044014110129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97343388815 + ... + 97343388948.

It is an arithmetic number, because the mean of its divisors is an integer number (3309675221988).

Almost surely, 2^{13044014110121} is an apocalyptic number.

It is an amenable number.

13044014110121 is a deficient number, since it is larger than the sum of its proper divisors (194686777831).

13044014110121 is an equidigital number, since it uses as much as digits as its factorization.

13044014110121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194686777830.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 13044014110121 its reverse (12101141044031), we get a palindrome (25145155154152).

The spelling of 13044014110121 in words is "thirteen trillion, forty-four billion, fourteen million, one hundred ten thousand, one hundred twenty-one".