Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …010110010101101001011 |
3 | 11121200220000111212211210 |
4 | 102332310122302231023 |
5 | 132332403403404003 |
6 | 2435122314024203 |
7 | 163145204112465 |
oct | 22766432625513 |
9 | 4550800455753 |
10 | 1304402013003 |
11 | 463214a26771 |
12 | 190975718063 |
13 | 9600a0b376b |
14 | 471c2069135 |
15 | 23de560a503 |
hex | 12fb46b2b4b |
1304402013003 has 4 divisors (see below), whose sum is σ = 1739202684008. Its totient is φ = 869601342000.
The previous prime is 1304402012971. The next prime is 1304402013053. The reversal of 1304402013003 is 3003102044031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1304402013003 - 25 = 1304402012971 is a prime.
It is a super-2 number, since 2×13044020130032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1304402013053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217400335498 + ... + 217400335503.
It is an arithmetic number, because the mean of its divisors is an integer number (434800671002).
Almost surely, 21304402013003 is an apocalyptic number.
1304402013003 is a deficient number, since it is larger than the sum of its proper divisors (434800671005).
1304402013003 is an equidigital number, since it uses as much as digits as its factorization.
1304402013003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 434800671004.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 1304402013003 its reverse (3003102044031), we get a palindrome (4307504057034).
The spelling of 1304402013003 in words is "one trillion, three hundred four billion, four hundred two million, thirteen thousand, three".
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