13044022400401 has 4 divisors (see below), whose sum is σ = 13080974305572. Its totient is φ = 13007070495232.

The previous prime is 13044022400393. The next prime is 13044022400417. The reversal of 13044022400401 is 10400422044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8046293886801 + 4997728513600 = 2836599^2 + 2235560^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044022400401 - 2³ = 13044022400393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044022401401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18475952056 + ... + 18475952761.

It is an arithmetic number, because the mean of its divisors is an integer number (3270243576393).

Almost surely, 2^{13044022400401} is an apocalyptic number.

It is an amenable number.

13044022400401 is a deficient number, since it is larger than the sum of its proper divisors (36951905171).

13044022400401 is an equidigital number, since it uses as much as digits as its factorization.

13044022400401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36951905170.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 13044022400401 its reverse (10400422044031), we get a palindrome (23444444444432).

The spelling of 13044022400401 in words is "thirteen trillion, forty-four billion, twenty-two million, four hundred thousand, four hundred one".