Search a number
-
+
13044023310301 = 127102708844963
BaseRepresentation
bin1011110111010000110001…
…1000000011011111011101
31201011222220102010101221121
42331310030120003133131
53202203124431412201
643424201440530541
72514254025513004
oct275641430033735
951158812111847
1013044023310301
114179a37113375
121568029020a51
1373807a431459
14331496a93c3b
1517948949a9a1
hexbdd0c6037dd

13044023310301 has 4 divisors (see below), whose sum is σ = 13146732155392. Its totient is φ = 12941314465212.

The previous prime is 13044023310251. The next prime is 13044023310361. The reversal of 13044023310301 is 10301332044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044023310301 - 29 = 13044023309789 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044023310361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51354422355 + ... + 51354422608.

It is an arithmetic number, because the mean of its divisors is an integer number (3286683038848).

Almost surely, 213044023310301 is an apocalyptic number.

It is an amenable number.

13044023310301 is a deficient number, since it is larger than the sum of its proper divisors (102708845091).

13044023310301 is a wasteful number, since it uses less digits than its factorization.

13044023310301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102708845090.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13044023310301 its reverse (10301332044031), we get a palindrome (23345355354332).

The spelling of 13044023310301 in words is "thirteen trillion, forty-four billion, twenty-three million, three hundred ten thousand, three hundred one".

Divisors: 1 127 102708844963 13044023310301