130440243433 has 2 divisors, whose sum is σ = 130440243434. Its totient is φ = 130440243432.

The previous prime is 130440243431. The next prime is 130440243587. The reversal of 130440243433 is 334342044031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116791695504 + 13648547929 = 341748^2 + 116827^2 .

It is a cyclic number.

It is not a de Polignac number, because 130440243433 - 2¹ = 130440243431 is a prime.

Together with 130440243431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 130440243395 and 130440243404.

It is not a weakly prime, because it can be changed into another prime (130440243431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220121716 + 65220121717.

It is an arithmetic number, because the mean of its divisors is an integer number (65220121717).

Almost surely, 2^130440243433 is an apocalyptic number.

It is an amenable number.

130440243433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440243433 is an equidigital number, since it uses as much as digits as its factorization.

130440243433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 130440243433 its reverse (334342044031), we get a palindrome (464782287464).

The spelling of 130440243433 in words is "one hundred thirty billion, four hundred forty million, two hundred forty-three thousand, four hundred thirty-three".