Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …100110100101010111101 |
3 | 11121200220001111221002000 |
4 | 102332310130310222331 |
5 | 132332404022422331 |
6 | 2435122333252513 |
7 | 163145211460500 |
oct | 22766434645275 |
9 | 4550801457060 |
10 | 1304402545341 |
11 | 46321525a715 |
12 | 190975934139 |
13 | 9600a23bb5c |
14 | 471c2167137 |
15 | 23de56b30e6 |
hex | 12fb4734abd |
1304402545341 has 48 divisors (see below), whose sum is σ = 2267843587200. Its totient is φ = 738776578176.
The previous prime is 1304402545301. The next prime is 1304402545349. The reversal of 1304402545341 is 1435452044031.
1304402545341 is a `hidden beast` number, since 1 + 30 + 4 + 40 + 2 + 54 + 534 + 1 = 666.
It is not a de Polignac number, because 1304402545341 - 210 = 1304402544317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1304402545296 and 1304402545305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304402545349) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4213081 + ... + 4512078.
It is an arithmetic number, because the mean of its divisors is an integer number (47246741400).
Almost surely, 21304402545341 is an apocalyptic number.
It is an amenable number.
1304402545341 is a deficient number, since it is larger than the sum of its proper divisors (963441041859).
1304402545341 is a wasteful number, since it uses less digits than its factorization.
1304402545341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8725295 (or 8725282 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 36.
Adding to 1304402545341 its reverse (1435452044031), we get a palindrome (2739854589372).
The spelling of 1304402545341 in words is "one trillion, three hundred four billion, four hundred two million, five hundred forty-five thousand, three hundred forty-one".
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