13044034441113 has 8 divisors (see below), whose sum is σ = 18729895607808. Its totient is φ = 8027098117584.

The previous prime is 13044034441093. The next prime is 13044034441133. The reversal of 13044034441113 is 31114443044031.

13044034441113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13044034441093) and next prime (13044034441133).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13044034441113 - 2¹⁸ = 13044034178969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13044034441133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167231210745 + ... + 167231210822.

It is an arithmetic number, because the mean of its divisors is an integer number (2341236950976).

Almost surely, 2^{13044034441113} is an apocalyptic number.

13044034441113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13044034441113 is a deficient number, since it is larger than the sum of its proper divisors (5685861166695).

13044034441113 is a wasteful number, since it uses less digits than its factorization.

13044034441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 334462421583.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 13044034441113 its reverse (31114443044031), we get a palindrome (44158477485144).

The spelling of 13044034441113 in words is "thirteen trillion, forty-four billion, thirty-four million, four hundred forty-one thousand, one hundred thirteen".