13044043231 has 2 divisors, whose sum is σ = 13044043232. Its totient is φ = 13044043230.

The previous prime is 13044043213. The next prime is 13044043247. The reversal of 13044043231 is 13234044031.

Together with previous prime (13044043213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13044043231 - 2²⁹ = 12507172319 is a prime.

It is a super-2 number, since 2×13044043231² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044043196 and 13044043205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044043211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522021615 + 6522021616.

It is an arithmetic number, because the mean of its divisors is an integer number (6522021616).

Almost surely, 2^13044043231 is an apocalyptic number.

13044043231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044043231 is an equidigital number, since it uses as much as digits as its factorization.

13044043231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13044043231 its reverse (13234044031), we get a palindrome (26278087262).

The spelling of 13044043231 in words is "thirteen billion, forty-four million, forty-three thousand, two hundred thirty-one".