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1304406505357 = 1399384219463
BaseRepresentation
bin10010111110110100101…
…011111011011110001101
311121200220022222010012021
4102332310223323132031
5132332411031132412
62435122554210141
7163145260232644
oct22766453733615
94550808863167
101304406505357
1146321751495a
12190977123951
139600acc7467
14471c28b835b
1523de5be6607
hex12fb4afb78d

1304406505357 has 4 divisors (see below), whose sum is σ = 1313790724960. Its totient is φ = 1295022285756.

The previous prime is 1304406505307. The next prime is 1304406505379. The reversal of 1304406505357 is 7535056044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304406505357 - 219 = 1304405981069 is a prime.

It is a super-2 number, since 2×13044065053572 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304406505307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4692109593 + ... + 4692109870.

It is an arithmetic number, because the mean of its divisors is an integer number (328447681240).

Almost surely, 21304406505357 is an apocalyptic number.

It is an amenable number.

1304406505357 is a deficient number, since it is larger than the sum of its proper divisors (9384219603).

1304406505357 is an equidigital number, since it uses as much as digits as its factorization.

1304406505357 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9384219602.

The product of its (nonzero) digits is 756000, while the sum is 43.

The spelling of 1304406505357 in words is "one trillion, three hundred four billion, four hundred six million, five hundred five thousand, three hundred fifty-seven".

Divisors: 1 139 9384219463 1304406505357