Base | Representation |
---|---|
bin | 11101101010001010101001… |
… | …101101110010111101000011 |
3 | 122002212001000212002111110002 |
4 | 131222022221231302331003 |
5 | 114044121134024243321 |
6 | 1141231434155030215 |
7 | 36322023453043331 |
oct | 3552125155627503 |
9 | 562761025074402 |
10 | 130441004134211 |
11 | 386207a0275551 |
12 | 1276841043b36b |
13 | 57a26c2ccc924 |
14 | 242d542034b51 |
15 | 101310abc520b |
hex | 76a2a9b72f43 |
130441004134211 has 2 divisors, whose sum is σ = 130441004134212. Its totient is φ = 130441004134210.
The previous prime is 130441004134183. The next prime is 130441004134271. The reversal of 130441004134211 is 112431400144031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130441004134211 is a prime.
It is not a weakly prime, because it can be changed into another prime (130441004134271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220502067105 + 65220502067106.
It is an arithmetic number, because the mean of its divisors is an integer number (65220502067106).
Almost surely, 2130441004134211 is an apocalyptic number.
130441004134211 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441004134211 is an equidigital number, since it uses as much as digits as its factorization.
130441004134211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 130441004134211 its reverse (112431400144031), we get a palindrome (242872404278242).
The spelling of 130441004134211 in words is "one hundred thirty trillion, four hundred forty-one billion, four million, one hundred thirty-four thousand, two hundred eleven".
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