Base | Representation |
---|---|
bin | 1011110111010001000100… |
… | …0000111010101101110011 |
3 | 1201012000002211120010001021 |
4 | 2331310101000322231303 |
5 | 3202203304342143443 |
6 | 43424213300520311 |
7 | 2514255662131606 |
oct | 275642100725563 |
9 | 51160084503037 |
10 | 13044101131123 |
11 | 4179a770362a7 |
12 | 156804b0b0097 |
13 | 7380905aa98a |
14 | 3314a315033d |
15 | 17949121d9ed |
hex | bdd1103ab73 |
13044101131123 has 2 divisors, whose sum is σ = 13044101131124. Its totient is φ = 13044101131122.
The previous prime is 13044101131079. The next prime is 13044101131181. The reversal of 13044101131123 is 32113110144031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13044101131123 - 221 = 13044099033971 is a prime.
It is a super-2 number, since 2×130441011311232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13044101131223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522050565561 + 6522050565562.
It is an arithmetic number, because the mean of its divisors is an integer number (6522050565562).
Almost surely, 213044101131123 is an apocalyptic number.
13044101131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044101131123 is an equidigital number, since it uses as much as digits as its factorization.
13044101131123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 13044101131123 its reverse (32113110144031), we get a palindrome (45157211275154).
The spelling of 13044101131123 in words is "thirteen trillion, forty-four billion, one hundred one million, one hundred thirty-one thousand, one hundred twenty-three".
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