Base | Representation |
---|---|
bin | 1011110111010001000100… |
… | …1000100000110111100011 |
3 | 1201012000002222022021120101 |
4 | 2331310101020200313203 |
5 | 3202203310344404103 |
6 | 43424213411323231 |
7 | 2514256015064233 |
oct | 275642110406743 |
9 | 51160088267511 |
10 | 13044103122403 |
11 | 4179a78176391 |
12 | 156804b8b0517 |
13 | 738090b27152 |
14 | 3314a350bcc3 |
15 | 1794914b3a1d |
hex | bdd11220de3 |
13044103122403 has 2 divisors, whose sum is σ = 13044103122404. Its totient is φ = 13044103122402.
The previous prime is 13044103122353. The next prime is 13044103122443. The reversal of 13044103122403 is 30422130144031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13044103122403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044103122443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522051561201 + 6522051561202.
It is an arithmetic number, because the mean of its divisors is an integer number (6522051561202).
Almost surely, 213044103122403 is an apocalyptic number.
13044103122403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044103122403 is an equidigital number, since it uses as much as digits as its factorization.
13044103122403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13044103122403 its reverse (30422130144031), we get a palindrome (43466233266434).
The spelling of 13044103122403 in words is "thirteen trillion, forty-four billion, one hundred three million, one hundred twenty-two thousand, four hundred three".
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