130441032014101 has 4 divisors (see below), whose sum is σ = 133216373120832. Its totient is φ = 127665690907372.

The previous prime is 130441032014057. The next prime is 130441032014107. The reversal of 130441032014101 is 101410230144031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130441032014101 - 2¹⁵ = 130441031981333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130441032014107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1387670553295 + ... + 1387670553388.

It is an arithmetic number, because the mean of its divisors is an integer number (33304093280208).

Almost surely, 2^{130441032014101} is an apocalyptic number.

It is an amenable number.

130441032014101 is a deficient number, since it is larger than the sum of its proper divisors (2775341106731).

130441032014101 is an equidigital number, since it uses as much as digits as its factorization.

130441032014101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2775341106730.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 130441032014101 its reverse (101410230144031), we get a palindrome (231851262158132).

The spelling of 130441032014101 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, fourteen thousand, one hundred one".