Base | Representation |
---|---|
bin | 111100101111011100… |
… | …1110011111001100001 |
3 | 110110200200012011002121 |
4 | 1321132321303321201 |
5 | 4114120423410334 |
6 | 135531320144241 |
7 | 12265312114636 |
oct | 1713671637141 |
9 | 413620164077 |
10 | 130441231969 |
11 | 50357747254 |
12 | 21344608081 |
13 | c3ba421639 |
14 | 6455d2418d |
15 | 35d696ddb4 |
hex | 1e5ee73e61 |
130441231969 has 2 divisors, whose sum is σ = 130441231970. Its totient is φ = 130441231968.
The previous prime is 130441231957. The next prime is 130441232017. The reversal of 130441231969 is 969132144031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 122822211600 + 7619020369 = 350460^2 + 87287^2 .
It is a cyclic number.
It is not a de Polignac number, because 130441231969 - 211 = 130441229921 is a prime.
It is a super-2 number, since 2×1304412319692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130441231909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220615984 + 65220615985.
It is an arithmetic number, because the mean of its divisors is an integer number (65220615985).
Almost surely, 2130441231969 is an apocalyptic number.
It is an amenable number.
130441231969 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441231969 is an equidigital number, since it uses as much as digits as its factorization.
130441231969 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 130441231969 in words is "one hundred thirty billion, four hundred forty-one million, two hundred thirty-one thousand, nine hundred sixty-nine".
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