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130441233221183 is a prime number
BaseRepresentation
bin11101101010001010110111…
…010111101100011000111111
3122002212001121211011022200202
4131222022313113230120333
5114044122121201034213
61141231513021114115
736322032234204353
oct3552126727543077
9562761554138622
10130441233221183
11386208a8614a25
12127684750b893b
1357a272b5cc451
14242d564629463
151013120d77b58
hex76a2b75ec63f

130441233221183 has 2 divisors, whose sum is σ = 130441233221184. Its totient is φ = 130441233221182.

The previous prime is 130441233221177. The next prime is 130441233221231. The reversal of 130441233221183 is 381122332144031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130441233221183 - 220 = 130441232172607 is a prime.

It is a super-3 number, since 3×1304412332211833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441233223183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220616610591 + 65220616610592.

It is an arithmetic number, because the mean of its divisors is an integer number (65220616610592).

Almost surely, 2130441233221183 is an apocalyptic number.

130441233221183 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441233221183 is an equidigital number, since it uses as much as digits as its factorization.

130441233221183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 38.

The spelling of 130441233221183 in words is "one hundred thirty trillion, four hundred forty-one billion, two hundred thirty-three million, two hundred twenty-one thousand, one hundred eighty-three".