13044123554441 has 8 divisors (see below), whose sum is σ = 14972668336320. Its totient is φ = 11131853412528.

The previous prime is 13044123554389. The next prime is 13044123554447. The reversal of 13044123554441 is 14445532144031.

13044123554441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13044123554441 - 2¹⁸ = 13044123292297 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13044123554447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4068658271 + ... + 4068661476.

It is an arithmetic number, because the mean of its divisors is an integer number (1871583542040).

Almost surely, 2^{13044123554441} is an apocalyptic number.

It is an amenable number.

13044123554441 is a deficient number, since it is larger than the sum of its proper divisors (1928544781879).

13044123554441 is an equidigital number, since it uses as much as digits as its factorization.

13044123554441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8137319983.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 13044123554441 its reverse (14445532144031), we get a palindrome (27489655698472).

The spelling of 13044123554441 in words is "thirteen trillion, forty-four billion, one hundred twenty-three million, five hundred fifty-four thousand, four hundred forty-one".