13044123554440 has 64 divisors (see below), whose sum is σ = 32213820087360. Its totient is φ = 4714217521920.

The previous prime is 13044123554389. The next prime is 13044123554447. The reversal of 13044123554440 is 4445532144031.

It is a Harshad number since it is a multiple of its sum of digits (40).

It is a junction number, because it is equal to n+sod(n) for n = 13044123554393 and 13044123554402.

It is not an unprimeable number, because it can be changed into a prime (13044123554447) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 90866119 + ... + 91009558.

It is an arithmetic number, because the mean of its divisors is an integer number (503340938865).

Almost surely, 2^{13044123554440} is an apocalyptic number.

13044123554440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13044123554440 is an abundant number, since it is smaller than the sum of its proper divisors (19169696532920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044123554440 is a wasteful number, since it uses less digits than its factorization.

13044123554440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 181875862 (or 181875858 counting only the distinct ones).

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 13044123554440 its reverse (4445532144031), we get a palindrome (17489655698471).

The spelling of 13044123554440 in words is "thirteen trillion, forty-four billion, one hundred twenty-three million, five hundred fifty-four thousand, four hundred forty".