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130441244024342 = 2106022961515599
BaseRepresentation
bin11101101010001010111000…
…000000111001111000010110
3122002212001122120111011211202
4131222022320000321320112
5114044122131432234332
61141231514044432502
736322032425060426
oct3552127000717026
9562761576434752
10130441244024342
1138620903723559
1212768478848732
1357a2730912754
14242d565c3c486
151013121cada62
hex76a2b8039e16

130441244024342 has 8 divisors (see below), whose sum is σ = 195662053764000. Its totient is φ = 65220559436344.

The previous prime is 130441244024303. The next prime is 130441244024347. The reversal of 130441244024342 is 243420442144031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 130441244024296 and 130441244024305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130441244024347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28637342 + ... + 32878257.

It is an arithmetic number, because the mean of its divisors is an integer number (24457756720500).

Almost surely, 2130441244024342 is an apocalyptic number.

130441244024342 is a deficient number, since it is larger than the sum of its proper divisors (65220809739658).

130441244024342 is a wasteful number, since it uses less digits than its factorization.

130441244024342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62575830.

The product of its (nonzero) digits is 294912, while the sum is 38.

Adding to 130441244024342 its reverse (243420442144031), we get a palindrome (373861686168373).

The spelling of 130441244024342 in words is "one hundred thirty trillion, four hundred forty-one billion, two hundred forty-four million, twenty-four thousand, three hundred forty-two".

Divisors: 1 2 1060229 2120458 61515599 123031198 65220622012171 130441244024342