Base | Representation |
---|---|
bin | 11101101010001010111000… |
… | …000000111001111000010110 |
3 | 122002212001122120111011211202 |
4 | 131222022320000321320112 |
5 | 114044122131432234332 |
6 | 1141231514044432502 |
7 | 36322032425060426 |
oct | 3552127000717026 |
9 | 562761576434752 |
10 | 130441244024342 |
11 | 38620903723559 |
12 | 12768478848732 |
13 | 57a2730912754 |
14 | 242d565c3c486 |
15 | 1013121cada62 |
hex | 76a2b8039e16 |
130441244024342 has 8 divisors (see below), whose sum is σ = 195662053764000. Its totient is φ = 65220559436344.
The previous prime is 130441244024303. The next prime is 130441244024347. The reversal of 130441244024342 is 243420442144031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 130441244024296 and 130441244024305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130441244024347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28637342 + ... + 32878257.
It is an arithmetic number, because the mean of its divisors is an integer number (24457756720500).
Almost surely, 2130441244024342 is an apocalyptic number.
130441244024342 is a deficient number, since it is larger than the sum of its proper divisors (65220809739658).
130441244024342 is a wasteful number, since it uses less digits than its factorization.
130441244024342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62575830.
The product of its (nonzero) digits is 294912, while the sum is 38.
Adding to 130441244024342 its reverse (243420442144031), we get a palindrome (373861686168373).
The spelling of 130441244024342 in words is "one hundred thirty trillion, four hundred forty-one billion, two hundred forty-four million, twenty-four thousand, three hundred forty-two".
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