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130441512531 = 31111069357103
BaseRepresentation
bin111100101111011101…
…0111000011001010011
3110110200200201101221210
41321132322320121103
54114121011400111
6135531330151203
712265314363621
oct1713672703123
9413620641853
10130441512531
1150357919020
1221344722503
13c3ba4bc255
146455d98511
1535d69c70a6
hex1e5eeb8653

130441512531 has 16 divisors (see below), whose sum is σ = 189750781440. Its totient is φ = 79048098720.

The previous prime is 130441512527. The next prime is 130441512541. The reversal of 130441512531 is 135215144031.

It is not a de Polignac number, because 130441512531 - 22 = 130441512527 is a prime.

It is a super-2 number, since 2×1304415125312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130441512541) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 186726 + ... + 543828.

It is an arithmetic number, because the mean of its divisors is an integer number (11859423840).

Almost surely, 2130441512531 is an apocalyptic number.

130441512531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

130441512531 is a deficient number, since it is larger than the sum of its proper divisors (59309268909).

130441512531 is a wasteful number, since it uses less digits than its factorization.

130441512531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 368186.

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 130441512531 its reverse (135215144031), we get a palindrome (265656656562).

The spelling of 130441512531 in words is "one hundred thirty billion, four hundred forty-one million, five hundred twelve thousand, five hundred thirty-one".

Divisors: 1 3 11 33 11069 33207 121759 357103 365277 1071309 3928133 11784399 3952773107 11858319321 43480504177 130441512531