Base | Representation |
---|---|
bin | 11101101010001011101011… |
… | …110001100100110010001011 |
3 | 122002212010220002112022010001 |
4 | 131222023223301210302023 |
5 | 114044130421234433003 |
6 | 1141232140145303431 |
7 | 36322063101242215 |
oct | 3552135361446213 |
9 | 562763802468101 |
10 | 130442112421003 |
11 | 3862120992a849 |
12 | 1276867b634b77 |
13 | 57a283b7c2426 |
14 | 242d6092cd5b5 |
15 | 101317314661d |
hex | 76a2ebc64c8b |
130442112421003 has 2 divisors, whose sum is σ = 130442112421004. Its totient is φ = 130442112421002.
The previous prime is 130442112420973. The next prime is 130442112421043. The reversal of 130442112421003 is 300124211244031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130442112421003 is a prime.
It is not a weakly prime, because it can be changed into another prime (130442112421043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221056210501 + 65221056210502.
It is an arithmetic number, because the mean of its divisors is an integer number (65221056210502).
Almost surely, 2130442112421003 is an apocalyptic number.
130442112421003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130442112421003 is an equidigital number, since it uses as much as digits as its factorization.
130442112421003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 130442112421003 its reverse (300124211244031), we get a palindrome (430566323665034).
The spelling of 130442112421003 in words is "one hundred thirty trillion, four hundred forty-two billion, one hundred twelve million, four hundred twenty-one thousand, three".
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