130442112421035 has 16 divisors (see below), whose sum is σ = 208809737637120. Its totient is φ = 69535007370080.

The previous prime is 130442112421003. The next prime is 130442112421043. The reversal of 130442112421035 is 530124211244031.

It is not a de Polignac number, because 130442112421035 - 2⁵ = 130442112421003 is a prime.

It is a super-4 number, since 4×130442112421035⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 130442112420987 and 130442112421005.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2132421801 + ... + 2132482970.

It is an arithmetic number, because the mean of its divisors is an integer number (13050608602320).

Almost surely, 2^{130442112421035} is an apocalyptic number.

130442112421035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130442112421035 is a deficient number, since it is larger than the sum of its proper divisors (78367625216085).

130442112421035 is a wasteful number, since it uses less digits than its factorization.

130442112421035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4264906818.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 130442112421035 its reverse (530124211244031), we get a palindrome (660566323665066).

The spelling of 130442112421035 in words is "one hundred thirty trillion, four hundred forty-two billion, one hundred twelve million, four hundred twenty-one thousand, thirty-five".