13044241231 has 8 divisors (see below), whose sum is σ = 14911528064. Its totient is φ = 11177910360.

The previous prime is 13044241201. The next prime is 13044241241. The reversal of 13044241231 is 13214244031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13044241231 - 2⁷ = 13044241103 is a prime.

It is a super-2 number, since 2×13044241231² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044241196 and 13044241205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044241201) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209505 + ... + 264538.

It is an arithmetic number, because the mean of its divisors is an integer number (1863941008).

Almost surely, 2^13044241231 is an apocalyptic number.

13044241231 is a deficient number, since it is larger than the sum of its proper divisors (1867286833).

13044241231 is an equidigital number, since it uses as much as digits as its factorization.

13044241231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 477981.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044241231 its reverse (13214244031), we get a palindrome (26258485262).

The spelling of 13044241231 in words is "thirteen billion, forty-four million, two hundred forty-one thousand, two hundred thirty-one".