1304424343133 has 4 divisors (see below), whose sum is σ = 1317088657248. Its totient is φ = 1291760029020.

The previous prime is 1304424343099. The next prime is 1304424343147. The reversal of 1304424343133 is 3313434244031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1304424343133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304424343093 and 1304424343102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304424349133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6332156903 + ... + 6332157108.

It is an arithmetic number, because the mean of its divisors is an integer number (329272164312).

Almost surely, 2^{1304424343133} is an apocalyptic number.

It is an amenable number.

1304424343133 is a deficient number, since it is larger than the sum of its proper divisors (12664314115).

1304424343133 is a wasteful number, since it uses less digits than its factorization.

1304424343133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12664314114.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 1304424343133 its reverse (3313434244031), we get a palindrome (4617858587164).

The spelling of 1304424343133 in words is "one trillion, three hundred four billion, four hundred twenty-four million, three hundred forty-three thousand, one hundred thirty-three".