1304425033130 has 24 divisors (see below), whose sum is σ = 2370982347972. Its totient is φ = 516704242944.

The previous prime is 1304425033127. The next prime is 1304425033133. The reversal of 1304425033130 is 313305244031.

It is an interprime number because it is at equal distance from previous prime (1304425033127) and next prime (1304425033133).

It can be written as a sum of positive squares in 2 ways, for example, as 1228056263329 + 76368769801 = 1108177^2 + 276349^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1304425033093 and 1304425033102.

It is not an unprimeable number, because it can be changed into a prime (1304425033133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6041639 + ... + 6253818.

Almost surely, 2^{1304425033130} is an apocalyptic number.

1304425033130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1304425033130 is a deficient number, since it is larger than the sum of its proper divisors (1066557314842).

1304425033130 is a wasteful number, since it uses less digits than its factorization.

1304425033130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12295670 (or 12295567 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 29.

The spelling of 1304425033130 in words is "one trillion, three hundred four billion, four hundred twenty-five million, thirty-three thousand, one hundred thirty".