Base | Representation |
---|---|
bin | 10010111110110101110… |
… | …011000011011010111111 |
3 | 11121200221122001101000220 |
4 | 102332311303003122333 |
5 | 132332430314301033 |
6 | 2435124501552423 |
7 | 163145604555633 |
oct | 22766563033277 |
9 | 4550848041026 |
10 | 1304425150143 |
11 | 463226a99a75 |
12 | 190981415713 |
13 | 96011b24a8b |
14 | 471c516cdc3 |
15 | 23de767abb3 |
hex | 12fb5cc36bf |
1304425150143 has 4 divisors (see below), whose sum is σ = 1739233533528. Its totient is φ = 869616766760.
The previous prime is 1304425150117. The next prime is 1304425150159. The reversal of 1304425150143 is 3410515244031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1304425150143 - 29 = 1304425149631 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304425157143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217404191688 + ... + 217404191693.
It is an arithmetic number, because the mean of its divisors is an integer number (434808383382).
Almost surely, 21304425150143 is an apocalyptic number.
1304425150143 is a deficient number, since it is larger than the sum of its proper divisors (434808383385).
1304425150143 is an equidigital number, since it uses as much as digits as its factorization.
1304425150143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434808383384.
The product of its (nonzero) digits is 28800, while the sum is 33.
The spelling of 1304425150143 in words is "one trillion, three hundred four billion, four hundred twenty-five million, one hundred fifty thousand, one hundred forty-three".
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