Base | Representation |
---|---|
bin | 111100101111011111… |
… | …0110110011100100001 |
3 | 110110200202200021101011 |
4 | 1321132332312130201 |
5 | 4114121243144441 |
6 | 135531404340521 |
7 | 12265326256456 |
oct | 1713676663441 |
9 | 413622607334 |
10 | 130442553121 |
11 | 50358469911 |
12 | 21344b44741 |
13 | c3ba794a9a |
14 | 645618982d |
15 | 35d6b30581 |
hex | 1e5efb6721 |
130442553121 has 8 divisors (see below), whose sum is σ = 133481114624. Its totient is φ = 127404219600.
The previous prime is 130442553079. The next prime is 130442553191. The reversal of 130442553121 is 121355244031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130442553121 - 27 = 130442552993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130442553191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1787296 + ... + 1858846.
It is an arithmetic number, because the mean of its divisors is an integer number (16685139328).
Almost surely, 2130442553121 is an apocalyptic number.
It is an amenable number.
130442553121 is a deficient number, since it is larger than the sum of its proper divisors (3038561503).
130442553121 is an equidigital number, since it uses as much as digits as its factorization.
130442553121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113991.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 130442553121 its reverse (121355244031), we get a palindrome (251797797152).
The spelling of 130442553121 in words is "one hundred thirty billion, four hundred forty-two million, five hundred fifty-three thousand, one hundred twenty-one".
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