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13044303121327 is a prime number
BaseRepresentation
bin1011110111010001110100…
…0011011100101110101111
31201012000121220122021111221
42331310131003130232233
53202204213044340302
643424245314124211
72514263664045412
oct275643503345657
951160556567457
1013044303121327
11417a070058555
1215680a6880667
137380c33b0aca
143314c1ccdb79
151794a3d1c937
hexbdd1d0dcbaf

13044303121327 has 2 divisors, whose sum is σ = 13044303121328. Its totient is φ = 13044303121326.

The previous prime is 13044303121189. The next prime is 13044303121331. The reversal of 13044303121327 is 72312130344031.

It is a strong prime.

It is an emirp because it is prime and its reverse (72312130344031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13044303121327 - 211 = 13044303119279 is a prime.

It is a super-2 number, since 2×130443031213272 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044303121292 and 13044303121301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044303121337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522151560663 + 6522151560664.

It is an arithmetic number, because the mean of its divisors is an integer number (6522151560664).

Almost surely, 213044303121327 is an apocalyptic number.

13044303121327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044303121327 is an equidigital number, since it uses as much as digits as its factorization.

13044303121327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 34.

Adding to 13044303121327 its reverse (72312130344031), we get a palindrome (85356433465358).

The spelling of 13044303121327 in words is "thirteen trillion, forty-four billion, three hundred three million, one hundred twenty-one thousand, three hundred twenty-seven".