Base | Representation |
---|---|
bin | 111100101111100000… |
… | …0111100111101010011 |
3 | 110110200210201021011011 |
4 | 1321133000330331103 |
5 | 4114121413312313 |
6 | 135531424231351 |
7 | 12265334042665 |
oct | 1713700747523 |
9 | 413623637134 |
10 | 130443104083 |
11 | 50358805856 |
12 | 2134516b557 |
13 | c3ba9287b6 |
14 | 6456290535 |
15 | 35d6bdd93d |
hex | 1e5f03cf53 |
130443104083 has 2 divisors, whose sum is σ = 130443104084. Its totient is φ = 130443104082.
The previous prime is 130443104081. The next prime is 130443104119. The reversal of 130443104083 is 380401344031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130443104083 - 21 = 130443104081 is a prime.
Together with 130443104081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (130443104081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221552041 + 65221552042.
It is an arithmetic number, because the mean of its divisors is an integer number (65221552042).
Almost surely, 2130443104083 is an apocalyptic number.
130443104083 is a deficient number, since it is larger than the sum of its proper divisors (1).
130443104083 is an equidigital number, since it uses as much as digits as its factorization.
130443104083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
The spelling of 130443104083 in words is "one hundred thirty billion, four hundred forty-three million, one hundred four thousand, eighty-three".
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