13044312144113 has 4 divisors (see below), whose sum is σ = 13730854888560. Its totient is φ = 12357769399668.

The previous prime is 13044312143983. The next prime is 13044312144161. The reversal of 13044312144113 is 31144121344031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13044312144113 - 2¹² = 13044312140017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13044312144113.

It is not an unprimeable number, because it can be changed into a prime (13044312444113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343271372195 + ... + 343271372232.

It is an arithmetic number, because the mean of its divisors is an integer number (3432713722140).

Almost surely, 2^{13044312144113} is an apocalyptic number.

It is an amenable number.

13044312144113 is a deficient number, since it is larger than the sum of its proper divisors (686542744447).

13044312144113 is an equidigital number, since it uses as much as digits as its factorization.

13044312144113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 686542744446.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 13044312144113 its reverse (31144121344031), we get a palindrome (44188433488144).

The spelling of 13044312144113 in words is "thirteen trillion, forty-four billion, three hundred twelve million, one hundred forty-four thousand, one hundred thirteen".