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130443131003 = 532461191151
BaseRepresentation
bin111100101111100000…
…1000011100001111011
3110110200210202122002012
41321133001003201323
54114121420143003
6135531425000135
712265334214323
oct1713701034173
9413623678065
10130443131003
1150358823aa9
122134518304b
13c3ba937b23
14645629a283
1535d6be68d8
hex1e5f04387b

130443131003 has 4 divisors (see below), whose sum is σ = 132904322208. Its totient is φ = 127981939800.

The previous prime is 130443130931. The next prime is 130443131033. The reversal of 130443131003 is 300131344031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130443131003 - 212 = 130443126907 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130443131003.

It is not an unprimeable number, because it can be changed into a prime (130443131033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1230595523 + ... + 1230595628.

It is an arithmetic number, because the mean of its divisors is an integer number (33226080552).

Almost surely, 2130443131003 is an apocalyptic number.

130443131003 is a deficient number, since it is larger than the sum of its proper divisors (2461191205).

130443131003 is an equidigital number, since it uses as much as digits as its factorization.

130443131003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2461191204.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130443131003 its reverse (300131344031), we get a palindrome (430574475034).

The spelling of 130443131003 in words is "one hundred thirty billion, four hundred forty-three million, one hundred thirty-one thousand, three".

Divisors: 1 53 2461191151 130443131003