Base | Representation |
---|---|
bin | 111100101111100000… |
… | …1110100011001000101 |
3 | 110110200211010210121201 |
4 | 1321133001310121011 |
5 | 4114121443044031 |
6 | 135531433142501 |
7 | 12265336006654 |
oct | 1713701643105 |
9 | 413624123551 |
10 | 130443331141 |
11 | 50358950402 |
12 | 2134525aa31 |
13 | c3ba9a7c56 |
14 | 645630d19b |
15 | 35d6c35d61 |
hex | 1e5f074645 |
130443331141 has 2 divisors, whose sum is σ = 130443331142. Its totient is φ = 130443331140.
The previous prime is 130443331127. The next prime is 130443331147. The reversal of 130443331141 is 141133344031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76272630625 + 54170700516 = 276175^2 + 232746^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130443331141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130443331147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221665570 + 65221665571.
It is an arithmetic number, because the mean of its divisors is an integer number (65221665571).
Almost surely, 2130443331141 is an apocalyptic number.
It is an amenable number.
130443331141 is a deficient number, since it is larger than the sum of its proper divisors (1).
130443331141 is an equidigital number, since it uses as much as digits as its factorization.
130443331141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 130443331141 its reverse (141133344031), we get a palindrome (271576675172).
The spelling of 130443331141 in words is "one hundred thirty billion, four hundred forty-three million, three hundred thirty-one thousand, one hundred forty-one".
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