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130443331141 is a prime number
BaseRepresentation
bin111100101111100000…
…1110100011001000101
3110110200211010210121201
41321133001310121011
54114121443044031
6135531433142501
712265336006654
oct1713701643105
9413624123551
10130443331141
1150358950402
122134525aa31
13c3ba9a7c56
14645630d19b
1535d6c35d61
hex1e5f074645

130443331141 has 2 divisors, whose sum is σ = 130443331142. Its totient is φ = 130443331140.

The previous prime is 130443331127. The next prime is 130443331147. The reversal of 130443331141 is 141133344031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76272630625 + 54170700516 = 276175^2 + 232746^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130443331141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130443331147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221665570 + 65221665571.

It is an arithmetic number, because the mean of its divisors is an integer number (65221665571).

Almost surely, 2130443331141 is an apocalyptic number.

It is an amenable number.

130443331141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130443331141 is an equidigital number, since it uses as much as digits as its factorization.

130443331141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 130443331141 its reverse (141133344031), we get a palindrome (271576675172).

The spelling of 130443331141 in words is "one hundred thirty billion, four hundred forty-three million, three hundred thirty-one thousand, one hundred forty-one".