Base | Representation |
---|---|
bin | 10010111110110110010… |
… | …010010000111101001001 |
3 | 11121200222012110001111011 |
4 | 102332312102100331021 |
5 | 132332434413111131 |
6 | 2435125353203521 |
7 | 163146034243600 |
oct | 22766622207511 |
9 | 4550865401434 |
10 | 1304433332041 |
11 | 463230678174 |
12 | 1909841005a1 |
13 | 9601372ac38 |
14 | 471c629ca37 |
15 | 23de82450b1 |
hex | 12fb6490f49 |
1304433332041 has 24 divisors (see below), whose sum is σ = 1606984253856. Its totient is φ = 1052104233600.
The previous prime is 1304433331997. The next prime is 1304433332047. The reversal of 1304433332041 is 1402333344031.
It is not a de Polignac number, because 1304433332041 - 217 = 1304433200969 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1304433331994 and 1304433332012.
It is not an unprimeable number, because it can be changed into a prime (1304433332047) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4052470 + ... + 4362496.
It is an arithmetic number, because the mean of its divisors is an integer number (66957677244).
Almost surely, 21304433332041 is an apocalyptic number.
It is an amenable number.
1304433332041 is a deficient number, since it is larger than the sum of its proper divisors (302550921815).
1304433332041 is a wasteful number, since it uses less digits than its factorization.
1304433332041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 315109 (or 315102 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 1304433332041 its reverse (1402333344031), we get a palindrome (2706766676072).
The spelling of 1304433332041 in words is "one trillion, three hundred four billion, four hundred thirty-three million, three hundred thirty-two thousand, forty-one".
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