Base | Representation |
---|---|
bin | 1011110111010001111101… |
… | …1000111110110011011111 |
3 | 1201012000201122101210110122 |
4 | 2331310133120332303133 |
5 | 3202204303113222401 |
6 | 43424253234225155 |
7 | 2514264651166316 |
oct | 275643730766337 |
9 | 51160648353418 |
10 | 13044342320351 |
11 | 417a0901a1341 |
12 | 15680b7a251bb |
13 | 7380cb556bb4 |
14 | 3314c71b527d |
15 | 1794a74b221b |
hex | bdd1f63ecdf |
13044342320351 has 2 divisors, whose sum is σ = 13044342320352. Its totient is φ = 13044342320350.
The previous prime is 13044342320333. The next prime is 13044342320441. The reversal of 13044342320351 is 15302324344031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13044342320351 - 234 = 13027162451167 is a prime.
It is a super-2 number, since 2×130443423203512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13044342320311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522171160175 + 6522171160176.
It is an arithmetic number, because the mean of its divisors is an integer number (6522171160176).
Almost surely, 213044342320351 is an apocalyptic number.
13044342320351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044342320351 is an equidigital number, since it uses as much as digits as its factorization.
13044342320351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 13044342320351 its reverse (15302324344031), we get a palindrome (28346666664382).
The spelling of 13044342320351 in words is "thirteen trillion, forty-four billion, three hundred forty-two million, three hundred twenty thousand, three hundred fifty-one".
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