Base | Representation |
---|---|
bin | 1011110111010100111011… |
… | …1101011011010101010101 |
3 | 1201012002210021010121210022 |
4 | 2331311032331123111111 |
5 | 3202212421420403131 |
6 | 43424504344034525 |
7 | 2514323511610421 |
oct | 275651675332525 |
9 | 51162707117708 |
10 | 13045140403541 |
11 | 417a45a743024 |
12 | 156829b162a45 |
13 | 7381c79b847c |
14 | 3315611a1b81 |
15 | 1795025ab37b |
hex | bdd4ef5b555 |
13045140403541 has 2 divisors, whose sum is σ = 13045140403542. Its totient is φ = 13045140403540.
The previous prime is 13045140403507. The next prime is 13045140403549. The reversal of 13045140403541 is 14530404154031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11130664150225 + 1914476253316 = 3336265^2 + 1383646^2 .
It is a cyclic number.
It is not a de Polignac number, because 13045140403541 - 234 = 13027960534357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13045140403549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522570201770 + 6522570201771.
It is an arithmetic number, because the mean of its divisors is an integer number (6522570201771).
Almost surely, 213045140403541 is an apocalyptic number.
It is an amenable number.
13045140403541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13045140403541 is an equidigital number, since it uses as much as digits as its factorization.
13045140403541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 13045140403541 its reverse (14530404154031), we get a palindrome (27575544557572).
The spelling of 13045140403541 in words is "thirteen trillion, forty-five billion, one hundred forty million, four hundred three thousand, five hundred forty-one".
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