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13045502333 is a prime number
BaseRepresentation
bin11000010011001001…
…01001000101111101
31020200011102011221002
430021210221011331
5203204122033313
65554254220045
7641164640333
oct141144510575
936604364832
1013045502333
115594933a96
122640ab4625
1312cb943b66
148ba811b53
1551543e058
hex30992917d

13045502333 has 2 divisors, whose sum is σ = 13045502334. Its totient is φ = 13045502332.

The previous prime is 13045502317. The next prime is 13045502359. The reversal of 13045502333 is 33320554031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9989402809 + 3056099524 = 99947^2 + 55282^2 .

It is a cyclic number.

It is not a de Polignac number, because 13045502333 - 24 = 13045502317 is a prime.

It is a super-2 number, since 2×130455023332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13045502296 and 13045502305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13045502033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522751166 + 6522751167.

It is an arithmetic number, because the mean of its divisors is an integer number (6522751167).

Almost surely, 213045502333 is an apocalyptic number.

It is an amenable number.

13045502333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13045502333 is an equidigital number, since it uses as much as digits as its factorization.

13045502333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 29.

The spelling of 13045502333 in words is "thirteen billion, forty-five million, five hundred two thousand, three hundred thirty-three".