Base | Representation |
---|---|
bin | 10010111110111101111… |
… | …001110100001000001001 |
3 | 11121201022002221101100220 |
4 | 102332331321310020021 |
5 | 132333220122441413 |
6 | 2435150200420253 |
7 | 163152145505331 |
oct | 22767571641011 |
9 | 4551262841326 |
10 | 1304561140233 |
11 | 46329683237a |
12 | 1909baa77689 |
13 | 96034059ba0 |
14 | 471d924c0c1 |
15 | 23e0458e223 |
hex | 12fbde74209 |
1304561140233 has 16 divisors (see below), whose sum is σ = 1891762694976. Its totient is φ = 794858270400.
The previous prime is 1304561140229. The next prime is 1304561140247. The reversal of 1304561140233 is 3320411654031.
It is not a de Polignac number, because 1304561140233 - 22 = 1304561140229 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1304561140194 and 1304561140203.
It is not an unprimeable number, because it can be changed into a prime (1304561140213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165591535 + ... + 165599412.
It is an arithmetic number, because the mean of its divisors is an integer number (118235168436).
Almost surely, 21304561140233 is an apocalyptic number.
1304561140233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1304561140233 is a deficient number, since it is larger than the sum of its proper divisors (587201554743).
1304561140233 is a wasteful number, since it uses less digits than its factorization.
1304561140233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 331191064.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 1304561140233 its reverse (3320411654031), we get a palindrome (4624972794264).
The spelling of 1304561140233 in words is "one trillion, three hundred four billion, five hundred sixty-one million, one hundred forty thousand, two hundred thirty-three".
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