1304687434641 has 4 divisors (see below), whose sum is σ = 1739583246192. Its totient is φ = 869791623092.

The previous prime is 1304687434637. The next prime is 1304687434663. The reversal of 1304687434641 is 1464347864031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304687434641 - 2² = 1304687434637 is a prime.

It is a super-2 number, since 2×1304687434641² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1304687434601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217447905771 + ... + 217447905776.

It is an arithmetic number, because the mean of its divisors is an integer number (434895811548).

Almost surely, 2^{1304687434641} is an apocalyptic number.

It is an amenable number.

1304687434641 is a deficient number, since it is larger than the sum of its proper divisors (434895811551).

1304687434641 is an equidigital number, since it uses as much as digits as its factorization.

1304687434641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434895811550.

The product of its (nonzero) digits is 4644864, while the sum is 51.

The spelling of 1304687434641 in words is "one trillion, three hundred four billion, six hundred eighty-seven million, four hundred thirty-four thousand, six hundred forty-one".