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13047842441 is a prime number
BaseRepresentation
bin11000010011011011…
…00100011010001001
31020200022211001221202
430021231210122021
5203210221424231
65554420313545
7641223554654
oct141155443211
936608731852
1013047842441
115596192167
1226418428b5
1312cc28303a
148bac6089b
155157525cb
hex309b64689

13047842441 has 2 divisors, whose sum is σ = 13047842442. Its totient is φ = 13047842440.

The previous prime is 13047842377. The next prime is 13047842449. The reversal of 13047842441 is 14424874031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8419897600 + 4627944841 = 91760^2 + 68029^2 .

It is a cyclic number.

It is not a de Polignac number, because 13047842441 - 26 = 13047842377 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13047842395 and 13047842404.

It is not a weakly prime, because it can be changed into another prime (13047842449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6523921220 + 6523921221.

It is an arithmetic number, because the mean of its divisors is an integer number (6523921221).

Almost surely, 213047842441 is an apocalyptic number.

It is an amenable number.

13047842441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13047842441 is an equidigital number, since it uses as much as digits as its factorization.

13047842441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 38.

The spelling of 13047842441 in words is "thirteen billion, forty-seven million, eight hundred forty-two thousand, four hundred forty-one".