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13048757497 is a prime number
BaseRepresentation
bin11000010011100010…
…00011110011111001
31020200101112120011201
430021301003303321
5203210440214442
65554452054201
7641234415526
oct141161036371
936611476151
1013048757497
115596757706
122642004361
1312cc5136a9
148bb01c14d
155158837b7
hex309c43cf9

13048757497 has 2 divisors, whose sum is σ = 13048757498. Its totient is φ = 13048757496.

The previous prime is 13048757489. The next prime is 13048757653. The reversal of 13048757497 is 79475784031.

13048757497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11331815401 + 1716942096 = 106451^2 + 41436^2 .

It is a cyclic number.

It is not a de Polignac number, because 13048757497 - 23 = 13048757489 is a prime.

It is not a weakly prime, because it can be changed into another prime (13048755497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6524378748 + 6524378749.

It is an arithmetic number, because the mean of its divisors is an integer number (6524378749).

Almost surely, 213048757497 is an apocalyptic number.

It is an amenable number.

13048757497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13048757497 is an equidigital number, since it uses as much as digits as its factorization.

13048757497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5927040, while the sum is 55.

The spelling of 13048757497 in words is "thirteen billion, forty-eight million, seven hundred fifty-seven thousand, four hundred ninety-seven".