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130501144573 is a prime number
BaseRepresentation
bin111100110001001111…
…0010110111111111101
3110110211211221000201221
41321202132112333331
54114231243111243
6135541300233341
712266640266152
oct1714236267775
9413754830657
10130501144573
11503885484a8
122136069b851
13c3c996a897
14645dc7c229
1535dbd55bed
hex1e62796ffd

130501144573 has 2 divisors, whose sum is σ = 130501144574. Its totient is φ = 130501144572.

The previous prime is 130501144549. The next prime is 130501144603. The reversal of 130501144573 is 375441105031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105460614009 + 25040530564 = 324747^2 + 158242^2 .

It is an emirp because it is prime and its reverse (375441105031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130501144573 - 25 = 130501144541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130501144513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65250572286 + 65250572287.

It is an arithmetic number, because the mean of its divisors is an integer number (65250572287).

Almost surely, 2130501144573 is an apocalyptic number.

It is an amenable number.

130501144573 is a deficient number, since it is larger than the sum of its proper divisors (1).

130501144573 is an equidigital number, since it uses as much as digits as its factorization.

130501144573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

The spelling of 130501144573 in words is "one hundred thirty billion, five hundred one million, one hundred forty-four thousand, five hundred seventy-three".