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130501205340232 = 2356928668981841
BaseRepresentation
bin11101101011000010101101…
…111111001011000001001000
3122010001210102101021121222011
4131223002231333023001020
5114101112432031341412
61141315232011505304
736326254344620446
oct3553025577130110
9563053371247864
10130501205340232
1138644283289681
1212778011758234
1357a829834701c
142432413501b96
151014980e1e7a7
hex76b0adfcb048

130501205340232 has 16 divisors (see below), whose sum is σ = 245119794749100. Its totient is φ = 65135926740480.

The previous prime is 130501205340221. The next prime is 130501205340241. The reversal of 130501205340232 is 232043502105031.

It can be written as a sum of positive squares in 2 ways, for example, as 117685048779076 + 12816156561156 = 10848274^2 + 3579966^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130501205340194 and 130501205340203.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14334486369 + ... + 14334495472.

Almost surely, 2130501205340232 is an apocalyptic number.

It is an amenable number.

130501205340232 is a deficient number, since it is larger than the sum of its proper divisors (114618589408868).

130501205340232 is a wasteful number, since it uses less digits than its factorization.

130501205340232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28668982416 (or 28668982412 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 130501205340232 its reverse (232043502105031), we get a palindrome (362544707445263).

The spelling of 130501205340232 in words is "one hundred thirty trillion, five hundred one billion, two hundred five million, three hundred forty thousand, two hundred thirty-two".

Divisors: 1 2 4 8 569 1138 2276 4552 28668981841 57337963682 114675927364 229351854728 16312650667529 32625301335058 65250602670116 130501205340232