Base | Representation |
---|---|
bin | 10010111111011001100… |
… | …000101000010001101110 |
3 | 11121202111101110100022121 |
4 | 102333121200220101232 |
5 | 132340142210101032 |
6 | 2435304143503154 |
7 | 163166501344633 |
oct | 22773140502156 |
9 | 4552441410277 |
10 | 1305024300142 |
11 | 463504217262 |
12 | 190b09bb7aba |
13 | 960a8cb37c4 |
14 | 4724097418a |
15 | 23e3007ba97 |
hex | 12fd982846e |
1305024300142 has 4 divisors (see below), whose sum is σ = 1957536450216. Its totient is φ = 652512150070.
The previous prime is 1305024300133. The next prime is 1305024300163. The reversal of 1305024300142 is 2410034205031.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×13050243001422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326256075034 + ... + 326256075037.
It is an arithmetic number, because the mean of its divisors is an integer number (489384112554).
Almost surely, 21305024300142 is an apocalyptic number.
1305024300142 is a deficient number, since it is larger than the sum of its proper divisors (652512150074).
1305024300142 is an equidigital number, since it uses as much as digits as its factorization.
1305024300142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652512150073.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1305024300142 its reverse (2410034205031), we get a palindrome (3715058505173).
The spelling of 1305024300142 in words is "one trillion, three hundred five billion, twenty-four million, three hundred thousand, one hundred forty-two".
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