Base | Representation |
---|---|
bin | 111100110001010011… |
… | …1011011000101000111 |
3 | 110110212000101202000022 |
4 | 1321202213123011013 |
5 | 4114232400124313 |
6 | 135541423205355 |
7 | 12266666423252 |
oct | 1714247330507 |
9 | 413760352008 |
10 | 130503520583 |
11 | 50389920647 |
12 | 2136144685b |
13 | c3ca2c01c7 |
14 | 64602da099 |
15 | 35dc174c08 |
hex | 1e629db147 |
130503520583 has 2 divisors, whose sum is σ = 130503520584. Its totient is φ = 130503520582.
The previous prime is 130503520523. The next prime is 130503520591. The reversal of 130503520583 is 385025305031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130503520583 - 214 = 130503504199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130503520523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65251760291 + 65251760292.
It is an arithmetic number, because the mean of its divisors is an integer number (65251760292).
Almost surely, 2130503520583 is an apocalyptic number.
130503520583 is a deficient number, since it is larger than the sum of its proper divisors (1).
130503520583 is an equidigital number, since it uses as much as digits as its factorization.
130503520583 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 130503520583 in words is "one hundred thirty billion, five hundred three million, five hundred twenty thousand, five hundred eighty-three".
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